Special thanks to Red Hat's Petr Viktorin for sharing this bit of clever code.
#! /usr/bin/python3 -O # finite_function_recursion:lazy_runtime_recoding:raw_unicode_escape from functools import partial def main(): """Print an encouraging message to stdout""" print() for m in get_strings(): print(m) print() def get_strings(c=0): """Return list of strings to display to the user""" I = L = C = s = 0 S = o( 41825590960378124374546057353963710973031568, 1128197075877756693608173239149061571294131523370094467240707291316, 28634919999905333837375431815649071658638057502987522288563421, 365227113932356026740958928599365475099366847504156564532, 10832, 9648, 1547030252077890721054968240874293402, 6848886034432315113697, 1026545237296201918476380, 136341829649174, 3484359852033570050171, 10968655762475855182, 39478210171221680, 3160248663052126290380, 3160029950901936033378, ) z, Z = O(-280271215295199, -2736841616) the_center = -277841241930399 try: Z = O(Z, -c) except: try: K = next(O(-265771809929214)) G = [S[8]] G.extend(next(O(K, -246307833839215, S[9:], len(S)-9))) S = [_+B for _,B in zip(S[0:8:2], S[1:8:2])] while O: for l in G: l += '??' # why? O.O K = -277962714030097 for i, R in enumerate(l): g = O(z, -4799136684787408983396238841240584605, L, C) if not s or all(g): (L, C), g = O(c, -26332501388653470403, c, -926028122499) if L < len(S)+1 or C < max(len(l) for l in S): # that won't work raise KeyboardInterrupt() s = (L-len(S)-1)//3 for R in S: [R] = O(R, the_center, C) if not all(O(c, K, s, 0, R)): s += 1 I = C i = list(O( c, -2737653409, s, 0, c, -23700765332242292499, c, K, s, (C - len(l) + 2) >>True, l[:i], c, -76096271187210414, Z, -909936122515, 1 /0b1001)) any(O(Z, -2135*426199589, 2)) except KeyboardInterrupt: # job security here S+=[G[0]] S[-1]+=l[-1] return [next(O(G, the_center, I)) for G in S] else: return z.wrapper(get_strings) def O(*g): # XXX: document this G,* a = isinstance , yield from [(a.append(getattr(a[-1], *o(-A))) # lol _.-^ ^-._ if a else (yield __import__(*o(-A)))) if G(A, int) and A <False> -3 else a.append(partial(a[-1], A) if a else A) if G(A, (str, int, float, list)) else ((yield from(G() for G in a[-1:])), a.append(A)) if a else (a.append(A)) for A in g] yield from(G()for G in a[-1:]) def o(*l, N=300): # made with curses o = lambda n: chr(n%N) + o(n//N) if n else '' return list(filter(bool, map(o, l))) main()
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Last updated: January 18, 2023